27=23t-4.9t^2

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Solution for 27=23t-4.9t^2 equation: 



27=23t-4.9t^2

We move all terms to the left:

27-(23t-4.9t^2)=0

We get rid of parentheses

4.9t^2-23t+27=0

a = 4.9; b = -23; c = +27;
Δ = b2-4ac
Δ = -232-4·4.9·27
Δ = -0.20000000000005
Delta is less than zero, so there is no solution for the equation

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